Cookies Consent

This website uses cookies to ensure you get the best experience on our website.

Learn More
Home
hackerrank certification
javascript (basic)

Fizz Buzz - JavaScript (Basic) Certification test solution | HackerRank

1 min read

Solution:


 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
'use strict'

function  fizzBuzz(number) {
    for (let i = 1 ; i <= number ; i++) {
        if (i % 3 === 0 && i % 5 === 0) {
            console.log('FizzBuzz');
        } else if (i % 3 === 0) {
            console.log('Fizz');
        } else if (i % 5 === 0) {
            console.log('Buzz');
        } else {
            console.log(i);
        }
    }
}

fizzBuzz(10);
Labels : #hackerrank certification ,#javascript (basic) ,

Post a Comment